Experiment to find the concentration of the ethanedioic acid Essay Example for Free

Experiment to strike the concent dimensionn of the ethanedioic acid EssayI can mathematical function a foul up collection to find the overall concentration of the acid mixture, and as I already have the concentration of H2C2O4 , I can simply minus that from the total concentration to derive the concentration of the H2SO4. Both strong and weak acids will react with a metal, therefore I will react the acid mixture with magnesium metal. Quantities of chemicals to use As I have been told that the concentrations are almost 0. 1 mol dm-3 H2C2O4 and 0. 2 mol dm-3 H2SO4, I can say that the total concentration is approximately 0. 1+0. 2=0. 3 mol dm-3.I am going to use 25cm3 of the acid mixture, therefore total moles of acid mixture is 0. 3 x 0. 025 = 0. 0075 moles H2SO4 + Mg == MgSO4 + H2 and H2C2O4 + Mg == MgC2O4 + H2 I need these in one equation so I can rent the molar ratios, therefore I form this ionic equation. 4H+ + 2Mg == 2Mg2+ + 2H2 The molar ratio between the acid mixture hydrogen is 42(21), therefore (0. 0075/2)x24000=90cm3, this is less than 250cm3, so will fit into the measuring cylinder.I must ensure the Magnesium is in excess. So if I use approximately 0. 1grams, moles of Mg = 0. 1/24. 3=0.0042moles but 12 ratio so multiply by 2 to get 0. 0084moles, therefore there is more moles Mg than acid so it is in excess. Ethanedioic acid is a super poisonous carboxylic acid. It is corrosive and may cause burns. If it comes to contact with skin rinse with plenty of water immediately. Wear a lab coat to go along exposure to skin. Specimen calculation If 22cm3 of KMnO4 was needed for the redox titration, then 0. 022 x 0. 05= 1. 110-3 moles of KMnO4 . Using 52 ratio of 5C2O42- 2MnO4- moles of H2C2O4 is (1. 110-3 /2) x5=2. 7510-3 moles, and finally to get concentration 2.7510-3 /0. 025=0. 11 mol dm-3.Which is almost 0. 1mol dm-3 as suggested the concentration was approximately. The above was all from experiment 1, and now to get the concentration of the Sulp huric acid was experiment 2. If the volume of gas collected was 80cm3, then moles of Hydrogen would be (80/1000)/24=0. 0033moles, however 42 ratio with acid so multiply by 2 to get 0. 0066moles, and as I used 25cm3 acid, concentration is 0. 0066/(25/1000)=0. 27mol dm-3. To get the H2SO4 concentration minus the H2C2O4 concentration (0. 11), 0. 27-0. 11=0. 16mol dm-3, this is close to 0. 20mol dm-3